Optimal. Leaf size=119 \[ \frac{\tan ^5(c+d x)}{5 a^2 d}+\frac{\tan ^3(c+d x)}{3 a^2 d}-\frac{\tan (c+d x)}{a^2 d}-\frac{3 \tanh ^{-1}(\sin (c+d x))}{4 a^2 d}-\frac{\tan ^3(c+d x) \sec (c+d x)}{2 a^2 d}+\frac{3 \tan (c+d x) \sec (c+d x)}{4 a^2 d}+\frac{x}{a^2} \]
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Rubi [A] time = 0.190259, antiderivative size = 119, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.381, Rules used = {3888, 3886, 3473, 8, 2611, 3770, 2607, 30} \[ \frac{\tan ^5(c+d x)}{5 a^2 d}+\frac{\tan ^3(c+d x)}{3 a^2 d}-\frac{\tan (c+d x)}{a^2 d}-\frac{3 \tanh ^{-1}(\sin (c+d x))}{4 a^2 d}-\frac{\tan ^3(c+d x) \sec (c+d x)}{2 a^2 d}+\frac{3 \tan (c+d x) \sec (c+d x)}{4 a^2 d}+\frac{x}{a^2} \]
Antiderivative was successfully verified.
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Rule 3888
Rule 3886
Rule 3473
Rule 8
Rule 2611
Rule 3770
Rule 2607
Rule 30
Rubi steps
\begin{align*} \int \frac{\tan ^8(c+d x)}{(a+a \sec (c+d x))^2} \, dx &=\frac{\int (-a+a \sec (c+d x))^2 \tan ^4(c+d x) \, dx}{a^4}\\ &=\frac{\int \left (a^2 \tan ^4(c+d x)-2 a^2 \sec (c+d x) \tan ^4(c+d x)+a^2 \sec ^2(c+d x) \tan ^4(c+d x)\right ) \, dx}{a^4}\\ &=\frac{\int \tan ^4(c+d x) \, dx}{a^2}+\frac{\int \sec ^2(c+d x) \tan ^4(c+d x) \, dx}{a^2}-\frac{2 \int \sec (c+d x) \tan ^4(c+d x) \, dx}{a^2}\\ &=\frac{\tan ^3(c+d x)}{3 a^2 d}-\frac{\sec (c+d x) \tan ^3(c+d x)}{2 a^2 d}-\frac{\int \tan ^2(c+d x) \, dx}{a^2}+\frac{3 \int \sec (c+d x) \tan ^2(c+d x) \, dx}{2 a^2}+\frac{\operatorname{Subst}\left (\int x^4 \, dx,x,\tan (c+d x)\right )}{a^2 d}\\ &=-\frac{\tan (c+d x)}{a^2 d}+\frac{3 \sec (c+d x) \tan (c+d x)}{4 a^2 d}+\frac{\tan ^3(c+d x)}{3 a^2 d}-\frac{\sec (c+d x) \tan ^3(c+d x)}{2 a^2 d}+\frac{\tan ^5(c+d x)}{5 a^2 d}-\frac{3 \int \sec (c+d x) \, dx}{4 a^2}+\frac{\int 1 \, dx}{a^2}\\ &=\frac{x}{a^2}-\frac{3 \tanh ^{-1}(\sin (c+d x))}{4 a^2 d}-\frac{\tan (c+d x)}{a^2 d}+\frac{3 \sec (c+d x) \tan (c+d x)}{4 a^2 d}+\frac{\tan ^3(c+d x)}{3 a^2 d}-\frac{\sec (c+d x) \tan ^3(c+d x)}{2 a^2 d}+\frac{\tan ^5(c+d x)}{5 a^2 d}\\ \end{align*}
Mathematica [B] time = 5.58872, size = 495, normalized size = 4.16 \[ \frac{\cos ^4\left (\frac{1}{2} (c+d x)\right ) \sec ^2(c+d x) \left (-\frac{151 \sin \left (\frac{c}{2}\right )}{d \left (\cos \left (\frac{c}{2}\right )-\sin \left (\frac{c}{2}\right )\right ) \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^2}-\frac{151 \sin \left (\frac{c}{2}\right )}{d \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^2}+\frac{36 \sin \left (\frac{c}{2}\right )}{d \left (\cos \left (\frac{c}{2}\right )-\sin \left (\frac{c}{2}\right )\right ) \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^4}+\frac{36 \sin \left (\frac{c}{2}\right )}{d \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^4}+\frac{180 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )}{d}-\frac{180 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}{d}-\frac{\sec (c) \sin \left (\frac{d x}{2}\right ) \left (333 \cos \left (2 c+\frac{3 d x}{2}\right )+287 \cos \left (2 c+\frac{5 d x}{2}\right )+67 \cos \left (4 c+\frac{7 d x}{2}\right )+68 \cos \left (4 c+\frac{9 d x}{2}\right )+293 \cos \left (\frac{d x}{2}\right )\right ) \sec ^5(c+d x)}{2 d}+\frac{\cos \left (\frac{c}{2}\right ) \sec (c) \left (-43 \sin \left (\frac{c}{2}+d x\right )-43 \sin \left (\frac{3 c}{2}+d x\right )-346 \sin \left (\frac{3 c}{2}+2 d x\right )+346 \sin \left (\frac{5 c}{2}+2 d x\right )+149 \sin \left (\frac{5 c}{2}+3 d x\right )+149 \sin \left (\frac{7 c}{2}+3 d x\right )+308 \sin \left (\frac{c}{2}\right )\right ) \sec ^4(c+d x)}{4 d}+240 x\right )}{60 a^2 (\sec (c+d x)+1)^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.089, size = 269, normalized size = 2.3 \begin{align*} 2\,{\frac{\arctan \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) }{d{a}^{2}}}-{\frac{1}{5\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-5}}+{\frac{1}{d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-4}}-{\frac{19}{12\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-3}}+{\frac{1}{8\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-2}}+{\frac{7}{4\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-1}}-{\frac{3}{4\,d{a}^{2}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) }-{\frac{1}{5\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-5}}-{\frac{1}{d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-4}}-{\frac{19}{12\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-3}}-{\frac{1}{8\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-2}}+{\frac{7}{4\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-1}}+{\frac{3}{4\,d{a}^{2}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.75619, size = 406, normalized size = 3.41 \begin{align*} -\frac{\frac{2 \,{\left (\frac{15 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{110 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac{328 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac{530 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} + \frac{105 \, \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}}\right )}}{a^{2} - \frac{5 \, a^{2} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{10 \, a^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac{10 \, a^{2} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac{5 \, a^{2} \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} - \frac{a^{2} \sin \left (d x + c\right )^{10}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{10}}} - \frac{120 \, \arctan \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{2}} + \frac{45 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{2}} - \frac{45 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{2}}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.19154, size = 323, normalized size = 2.71 \begin{align*} \frac{120 \, d x \cos \left (d x + c\right )^{5} - 45 \, \cos \left (d x + c\right )^{5} \log \left (\sin \left (d x + c\right ) + 1\right ) + 45 \, \cos \left (d x + c\right )^{5} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \,{\left (68 \, \cos \left (d x + c\right )^{4} - 75 \, \cos \left (d x + c\right )^{3} + 4 \, \cos \left (d x + c\right )^{2} + 30 \, \cos \left (d x + c\right ) - 12\right )} \sin \left (d x + c\right )}{120 \, a^{2} d \cos \left (d x + c\right )^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\tan ^{8}{\left (c + d x \right )}}{\sec ^{2}{\left (c + d x \right )} + 2 \sec{\left (c + d x \right )} + 1}\, dx}{a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 10.3405, size = 184, normalized size = 1.55 \begin{align*} \frac{\frac{60 \,{\left (d x + c\right )}}{a^{2}} - \frac{45 \, \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right )}{a^{2}} + \frac{45 \, \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right )}{a^{2}} + \frac{2 \,{\left (105 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} - 530 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 328 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 110 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 15 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{5} a^{2}}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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